Help Thrid second and first order differential equation

klovely
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Help! Thrid second and first order differential equation!

I have no idea how to accomplish this problem. If anyone knows help please help me solve this example before I take my test!

Solve
y''' - y'' - y' + y - x = 0
 
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Have you never taken a course in differential equations? If not I wonder why you would be trying to solve an equation like this. If you have, this should be relatively easy. It is a "linear equation with constant coefficients". The associated homogeneous equation is y'''- y''- y'+ y= 0 which has characteristic equation r^3- r^2- r+ 1= 0. An obvious solution to that is r= 1 and then you can divide by r- 1 to get a quadratic equation to solve for the other two roots.

To find a specific solution to the entire equation, try y(x)= Ax+ B for some numbers A and B.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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