Help~ tmolo test i cant figuar out this

Thread starter skyliner34
Start date Apr 10, 2008
Tags

Test

AI Thread Summary

To find the electric field 2.5m from the center of a region with a charge density of ro=5.5E-15 R**(2.3), the bulk charge within the sphere can be calculated using the formula Q=(4/3)*Pi*(R^3)*ro. The discussion indicates that the answer in the back of the book is approximately 0.00241. Participants express difficulty in locating relevant information in their textbooks to solve the problem. The approach involves treating the bulk charge as equivalent to a point charge at the center of the sphere. This method is essential for determining the electric field in the specified region.

Apr 10, 2008

skyliner34

find the electric field 2.5m from the center of region of space with a charge density given by ro=5.5E-15 R**(2.3)

i flip all over the book, i still can't find anything to solve this question, can anyone help?
the ans from the back of the book is .00241

Last edited: Apr 10, 2008

Physics news on Phys.org

Apr 10, 2008

miknsk

AFAIR, it might be supposed that bulk charge within sphere is equal to the point charge
Q=(4/3)*Pi*(R^3)*ro placed into the center of sphere.

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »