Help to make a solenoid/Electromagnet.

AI Thread Summary
To create an electromagnet with a 20mm diameter and a 10mm diameter iron core, careful consideration of wire selection, number of turns, current, and voltage is essential. The relationship between the number of turns (N) and current (I) should be maintained as a constant to achieve the desired magnetic induction, ideally around 1 to 1.2 Tesla. The cross-sectional area of the coil must fit within the specified dimensions, and the wire's length can be calculated to determine its resistance, which will inform the voltage needed using Ohm's law (V = R * I). Additionally, factors such as whether the magnet will be continuously on or switched on and off will impact power consumption and temperature. Proper planning will ensure the electromagnet meets performance expectations.
Shahryar
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I need to make an electromagnet with maximum 20mm dia including winding.
I have an iron core of 10mm dia and 20mm length.

I can't decide
- which wire to choose,
- what no. of turns should i provide
- how much current should i pass through the wire.
- what should be the voltage.

Any help and advice will be highly appreciated.
Thank you
 
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Shahryar said:
- what no. of turns should i provide
- how much current should i pass through the wire.
Don't think of N and I separately. Think of N*I = some constant, which induces a constant magnetic induction ( B-field with the unit [Tesla] ).
How many Tesla do you want? ( I will suggest 1 - 1,2 Tesla max. ).
Shahryar said:
- which wire to choose,
Make some sketch of the cross section of the magnet: The area of the coil must be kept within your given limits: 20mm dia * 20mm length.
Shahryar said:
- what should be the voltage.
Calculate the length of the wire. Knowing the cross section area of the wire you can calculate the resistance of the wire.
V = R * I

The rest: Will the magnet be switched on constantly or on/off ( how much mean-power will it consume, what will its temperature be? ).
 
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