Help Undersanding The Voltaic Cell

  • Thread starter Thread starter coreluccio
  • Start date Start date
  • Tags Tags
    Cell
AI Thread Summary
Zinc metal reacts with aqueous copper (II) ions through an electrochemical process that requires a complete circuit, which is typically established using a salt bridge and connecting wires. The salt bridge allows for the movement of ions between the two separate jars, facilitating the flow of electrons. When zinc is placed in a solution containing copper (II) ions, zinc donates electrons to the copper ions, reducing them to solid copper. This reaction occurs despite the physical separation because the ions can migrate through the salt bridge, maintaining charge balance and enabling the electrochemical reaction to proceed.
coreluccio
Messages
35
Reaction score
2
Alright, so I understand how it works, except that, I don't get how zinc metal reacts with aqueous copper (II) ions if they are completely separated by two jars. How can a copper (II) ion pull the electrons from solid zinc when it can't even physically collide with zinc?
 
Chemistry news on Phys.org
They have to be connected by a salt-bridge, and also another (usually) wire to complete the circuit.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top