Help with a circuit problem (Zener Diode)

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Discussion Overview

The discussion revolves around a circuit problem involving a zener diode, specifically focusing on determining the current through the diode under various voltage conditions. Participants explore the application of relevant equations and clarify the behavior of the zener diode in different scenarios, including both positive and negative supply voltages.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant proposes the formula I = (Vs - Vd)/Req, where Vd is the voltage drop across the zener diode, and questions whether the initial formula used is correct.
  • Another participant clarifies that Vd equals Von when the current is positive and equals -Vz when the current is negative, emphasizing that the zener is not a source of emf.
  • There is a discussion about how to measure current and whether to exclude the diode in the initial calculations, particularly when Vs is 0.2V.
  • One participant calculates the current for Vs = 0.2V and arrives at a negative current, questioning the validity of the approach.
  • Another participant asserts that the zener conducts no current if Vz < Vs < Von, stating that if Vs is less than Von, the current is zero.
  • Confusion arises regarding the correct application of the conditions for current flow, particularly when Vs is negative, leading to further clarification on the calculations needed.
  • Participants engage in correcting each other's calculations and interpretations, particularly regarding the signs and values used in the equations.

Areas of Agreement / Disagreement

Participants generally agree on the principle that the zener diode does not conduct current under certain voltage conditions, but there is disagreement on the specifics of the calculations and interpretations of the conditions for current flow. The discussion remains unresolved regarding the correct application of the formulas and the implications of the zener diode's behavior in different scenarios.

Contextual Notes

There are limitations in the discussion regarding the assumptions made about the zener diode's operation, particularly in relation to the definitions of Vd and Vz. The participants have not fully resolved the mathematical steps involved in determining the current under varying supply voltages.

november1992
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Homework Statement



In the circuit below, a zener diode (VON = 0.7V, VZ = -5.7 V) is in series with two
resistors. Determine the current (I) if Vs is:

a) 6V b) 4V c) 0.2V d) – 0.2V e) – 4V f) – 6V

[PLAIN]http://img809.imageshack.us/img809/6995/zenerdiodecircuit.png

Homework Equations



I was thinking that I=V-Von/Req

The Attempt at a Solution


not sure if i have the correct formula.I'm not asking for the answer i Just want to know whether I'm using the correct formula. I was wondering what exactly is Vz
 
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You almost have the right formula, although I think you left out a parenthesis, and it's actually I = (Vs - Vd)/Req where Vd is the drop across the zener.

Vd = Von, I > 0
Vd = -Vz, I < 0

Note - the Zener is NOT as source of emf!
 
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So, when you say that:

Vd = Von, I > 0
Vd = -Vz, I < 0

Do you measure the current excluding the diode first?

Problem 1.c)
The voltage is 0.2V so would the current be measured excluding the diode to determine whether the current is negative and then, after figuring out the current, would you use that value to determine the value of Vd?

I=V/Req
I=0.2V/10ohm
I=0.02 Amps
Vd = Von, I > 0
then,
I=Vs-Vd/Req
I=0.2V-0.7V/10ohm
I=-0.05
 


november1992 said:
So, when you say that:

Vd = Von, I > 0
Vd = -Vz, I < 0

Do you measure the current excluding the diode first?

Problem 1.c)
The voltage is 0.2V so would the current be measured excluding the diode to determine whether the current is negative and then, after figuring out the current, would you use that value to determine the value of Vd?

I=V/Req
I=0.2V/10ohm
I=0.02 Amps
Vd = Von, I > 0
then,
I=Vs-Vd/Req
I=0.2V-0.7V/10ohm
I=-0.05

No. The zener conducts no current if Vz < Vs < Von. This is your golden rule. Remember that Vz is negative. No zener current means I = 0.

So when Vs > 0 you need Vs > Von to get any current. What you do is subtract Von from Vs and then compute the current. If it computes < 0 there is no current.

Likewise for Vs < 0. Subtract Vz from Vs. Remeber now Vs < 0. If current computes > 0 there is no current.
 
So I have to subtract the Von from the Vs?

So for a voltage of 6V, would the current be 0 since 0.7V-6V/10ohms=-0.53Amps
 
You contradicted yourself in those two sentences. Think about it. (Hint: the first one is correct).
 


rude man said:
No. The zener conducts no current if Vz < Vs < Von. This is your golden rule. Remember that Vz is negative. No zener current means I = 0.

So when Vs > 0 you need Vs > Von to get any current. What you do is subtract Von from Vs and then compute the current. If it computes < 0 there is no current.

Likewise for Vs < 0. Subtract Vz from Vs. Remeber now Vs < 0. If current computes > 0 there is no current.

So does this mean that if the voltage is 0.2V that I=0Amps because Vs<Von,
and if the voltage is -0.2V I=-0.09 Amps because [(-5.7V)-(-0.2V)]/10=0.09A?
 
Yes to the first part, no to the second.
To repeat: "Likewise for Vs < 0. Subtract Vz from Vs. Remeber now Vs < 0. If current computes > 0 there is no current. "

What is Vs - Vz? answer: -0.2 - (-5.7) = + 5.5V. Current computes to +5.5V/R > 0 so no current.

Again you wrote Vz - Vs when I said to compute Vs - Vz. Tsk tsk! :-)
 

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