Help with a physics/calc problem involving work.

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The discussion revolves around understanding the relationship between force, volume, and density in the context of work in calculus. Participants express confusion about how force (F) can be represented as the product of volume and density, given that force is typically defined as mass times acceleration (F=ma). Clarification is provided that in fluid mechanics, mass can be expressed as volume multiplied by density, leading to the equation W=Density*Volume*acceleration*distance for work done by fluids. The conversation highlights the assumption that mass and weight can be treated equivalently in this mathematical context. Overall, the discussion emphasizes the importance of understanding these relationships in solving calculus problems involving work and fluids.
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In my Calc II class, we are starting to learn applications regarding work. Now I know Work = the integral of (Force) x (Distance) dx, but the question involves a fluid. So the equation is
W= Integral of F x D dx, but we replace F= (Volume) x (Density). This is were I am confuse. How does (Volume) x (Density)=F?. Doesn't F=(mass) x (acceleration)? I don't see the relation between the F=V(density) and the F=ma.
 
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It doesn't. Must be a mistake. Volume * Density = mass, not force.
 
Must be volume*density*acceleration of fluid.
 
chaoseverlasting said:
Must be volume*density*acceleration of fluid.

I too believe this must be the case. In fluid mechanics parameters are frequently described through their volume density.
 
I asked my teacher, and because it's a math class, she said that we are to assume that mass and weight are equal.
 
what book are you using?

my Stewart 5th ed they do Work problems involving liquids to be:

W=F*d=m*a*d=Density*Volume*acceleration*distance
 
I'm using a book called Calculus 8th ed. by Larson, Hostetler and Edwards.
 
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