Algebraic Equations for Basic Tension in a Hanging Block System

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The discussion focuses on solving for the tensions in a hanging block system with a 5 kg block, where one side of the string is at a 30-degree angle and the other at 45 degrees. The equations derived include T1(cos 30) - T2(cos 45) = 0 for the x-direction and T1(sin 30) + T2(sin 45) - 50 N = 0 for the y-direction. Participants suggest rearranging the equations to express T1 in terms of T2, leading to T1 = T2(cos 45)/(cos 30). The conversation emphasizes using algebraic manipulation to isolate one variable and solve the system of equations effectively. The goal is to accurately determine the tensions in the system.
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Basic Tension question- 5 kg block hanging from a string with one side at 30 degrees and the otherside at 45 degrees.

Fnet,x=t1x-t2x=0
Gravity assumed at 10 m/s2 (in the book)
I got to:
T1(cos 30)-T2(Cos45)=0 for the total forces in the x direction and
T1(sin 30) + T2(sin 45)-(50 N)= 0 for the y direction

I know I am supposed to use algebra but i never was very good with numbers. How I got into AP physics, I'll never know! Thanks in advance!
 
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doing good. you have two unknowns in one equation. how about some rearranging to evaluate for one T and using some substitution?

Hint: What is T1 equal to? (not asking for the tension value)
 
hmmm t1= t2 (cos 45)/cos 30)

So now I have T2((cos45)/(cos30))-T2Cos45

For which I get .8164965809 hmmmmm where did i go wrong
 
Close, but not quite. You're right:

T1 = T2(cos45)/(cos 30)

now take this and use it for the T1 in the other equation, then solve for T2. You should be good to go.
 
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