Help with average speed/instantaneous speed

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The discussion focuses on understanding average speed and instantaneous speed in physics. The user initially struggles with calculating instantaneous speed at t = 20 seconds and average speed over the first 35 seconds. They clarify that average speed is determined by the area under the graph divided by time, while instantaneous speed is found using the slope of the tangent at a specific point on the graph. After resolving the average speed calculation, the user seeks further assistance with the instantaneous speed problem. The conversation emphasizes the importance of correctly interpreting displacement versus time graphs for these calculations.
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Help with average speed/instantaneous speed! :(

Homework Statement



2-P72.gif

1. EDIT: Figured this one out, now I just need to know about the 2nd question about instantaneous speed.
2. What is its instantaneous speed at t = 20 s?

Homework Equations



v= change in x/change in t

The Attempt at a Solution



I have no idea how to do this. My textbook doesn't really cover this section well, and I'm just starting out in Physics.
I did v=2/20 and came out with .1, but I think it's wrong.
 
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Bensky said:

Homework Statement



2-P72.gif

1. What is its average speed during the first 35 s?
2. What is its instantaneous speed at t = 20 s?

Homework Equations



v= change in x/change in t

The Attempt at a Solution



I have no idea how to do this. My textbook doesn't really cover this section well, and I'm just starting out in Physics.
I did v=2/20 and came out with .1, but I think it's wrong.


Is it average speed or average velocity.As it is a displacement versus time graph.
 
FedEx said:
Is it average speed or average velocity.As it is a displacement versus time graph.

Average speed. That's where I'm confused. Why would they give me that type of graph?
 
Average speed is the area of the graph divided by the time.
 
Sourabh N said:
Average speed is the area of the graph divided by the time.

Ok, well I figured out the average speed by doing d/t I think. Either way, it told me I was right, so now I just have the instantaneous speed problem that I don't understand. D:
 
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instanteneous speed is defined as the tangent to the curve at that point(time).
 
Sourabh N said:
instanteneous speed is defined as the tangent to the curve at that point(time).

So I would use the slope formula to find it?
 
Ya. How did u get the area under the curve.
 
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