Help with Bending Moment Diagram for Structure

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The discussion focuses on the challenges of drawing a bending moment diagram for a statically indeterminate structure with fixed joints. The initial calculations for the bending moments at the ends of the beam were incorrect, as the structure is not fixed-fixed. Participants suggest using methods like the stiffness matrix or moment distribution to analyze the frame, emphasizing the importance of member stiffness. Recommendations include simplifying the problem by utilizing symmetry and deriving equations based on the degrees of freedom. The conversation highlights the need for a deeper understanding of bending moment calculations in complex structures.
axe34
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Homework Statement


upload_2015-3-16_19-6-8.png

Hi I need help with drawing a bending moment diagram for this structure. All joints are rigid and it's fixed to the ground. I'm really struggling with this. I initially started with the horizontal beam (statically indeterminate) and found that the moments at the ends were FL/8 (ccw on left, and cw on right) and that F/2 was applied up at each end of the beam. However, this is not the correct answer! Also this answer doesn't give the correct answer for the vertical beams. I really don't know how to do this.

Homework Equations


d2v/ dx2 = -M (helps with statically indeterminate beams but this is not the only way to deal with them but I like this method and this is how I calculated the FL/8's)

The Attempt at a Solution


as above
 
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Your equation isn't complete.

Can you show your work on how you derived FL/8?
 
Hi

For a fixed-fixed beam only, there are BMs of FL/8 - this is a standard result. It would take pages + pages to show this, but it starts from the fact that d2v/dx2 = -M. Fl/8 isn't correct here in this structure.
 
You are right the beam is not fixed-fixed but your equation is not quite correct.

Do you know the stiffness matrix for a beam element?
 
Hi
I know nothing about stiffness etc. - only each beam is L length and the same as the others.
 
Generally the bending moment will be a function of the members' stiffness for a statically indeterminate frame. If all the members have the same stiffness (EI) then the term simply cancels out.

So you can use this method or you could do a moment distribution method. Have you studied either of these methods?
 
Hi
The only method I've ever used for 1 statically indeterminate beam is to do EI * d2v/dx2 = -M. I just don't know where to start on this one. If I was given one horizontal beam, fixed at both ends, then using this method I'd get moments of F*L /8 at the ends
 
OK, this will be a long process starting from such a basic formula.

The first step I would recommend is to simplify the problem using the symmetry of the frame and leave just two degrees of freedom.

The 2nd step I would recommend is to derive two equations from these two degrees of freedom.

Do you happen to know any formulae that cover the following conditions:

1) for beam fixed-pinned with a moment M at the pinned end - formula for dv/dx at pinned end?
2) for beam fixed-fixed with a displacement v at one end - formula for M at ends?
 

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