Help with bernoulli differential equation

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I need help with solving equation y'=(x^2-y^2)/xy as bernoulli differential equation.

I also tried to do it differently by plugging in y=xv, so I got f(v)=1/v-v.

Finally I got answer y=(+/-) [(x^4+c)^(1/2)]/[(x*2^(1/2)] but I still have no idea how to do it as bernoulli equation
 
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isn't this homework?
 
Thread 'Direction Fields and Isoclines'

Thread 'Direction Fields and Isoclines'

I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
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