Help with continous line graph (interval notation)

[Torshi]

Homework Statement

See attachment: what is the interval notation of the continuous line

Homework Equations

no equation

The Attempt at a Solution

(-2,-1)U(-1,inf) ? not sure then it goes to 1 then to -inf? There are two continuous lines
(-2,-1)U(-1,1)U(1,inf)? No...
i feel like an idiot on this problem

 

[SammyS]

Homework Statement

See attachment: what is the interval notation of the continuous line

Homework Equations

no equation

The Attempt at a Solution

(-2,-1)U(-1,inf) ? not sure then it goes to 1 then to -inf? There are two continuous lines
(-2,-1)U(-1,1)U(1,inf)? No...
i feel like an idiot on this problem

What is the function's value at x = 0 ?

 

[Torshi]

What is the function's value at x = 0 ?

idk inf?

 

[SammyS]

idk inf?

∞ is not a permissible value for a function.

Is the function even defined at x = 0 ?

 

[Torshi]

∞ is not a permissible value for a function.

Is the function even defined at x = 0 ?

Sorry and no it's not I believe. Nothings there. From -1 there is discontinuity and a jump to 1

 

[Torshi]

I'm really having trouble with this problem

 

[SammyS]

bump

Read the Forum rules regarding bumping.

 

[SammyS]

Sorry and no it's not I believe. Nothings there. From -1 there is discontinuity and a jump to 1

The function is not defined at x=0, so how can it be continuous there? (You said it was continuous on (-1,1) . )

 

[Torshi]

The function is not defined at x=0, so how can it be continuous there? (You said it was continuous on (-1,1) . )

I'm stuck after (-2,-1) if that's even right for the first continuous line

So there is a hole after -1. Then there is jump to 1 so that (-1,1) doesn't apply since at 0 it's undefined. So from 1 onto where? at 1 there are 2 holes, one going infinitely down and another that goes right

Not continuous:
1.) not defined
2.) limit DNE
3.) limit does not equal to evaluation --> is this the problem? this last one

 

[Torshi]

(-2,-1)U(-1,0)U(0,1)U(1,3)U(3,4) ? Nope.. How do I do this?

 

[SammyS]

I'm stuck after (-2,-1) if that's even right for the first continuous line

So there is a hole after -1. Then there is jump to 1 so that (-1,1) doesn't apply since at 0 it's undefined. So from 1 onto where? at 1 there are 2 holes, one going infinitely down and another that goes right

Not continuous:
1.) not defined
2.) limit DNE
3.) limit does not equal to evaluation --> is this the problem? this last one

What do you mean by "continuous line" ? You're looking for continuity over a set of intervals.

(-2,-1)U(-1,0)U(0,1)U(1,3)U(3,4) ? Nope.. How do I do this?

Why do you say the graph is not continuous at x=3 ? (Which of the three above reasons?)

 

[Torshi]

I know the answer finally. The problem was that I had it all along, but everytime I typed it into the box online it would not recognize it due to simple [] in which that's why I was so confused...

The answer is: [-2,-1)U(-1,0)U(0,1)U(1,4]

-Thanks

 

[Torshi]

What do you mean by "continuous line" ? You're looking for continuity over a set of intervals.



Why do you say the graph is not continuous at x=3 ? (Which of the three above reasons?)

(1,4]

The previous answers I was posting was simply out of confusion since I've typed in the right answer before and was marked as incorrect, hence my confusion.

Thank you

 

[Mark44]

Homework Statement

See attachment: what is the interval notation of the continuous line

Homework Equations

no equation

The Attempt at a Solution

(-2,-1)U(-1,inf) ? not sure then it goes to 1 then to -inf? There are two continuous lines
(-2,-1)U(-1,1)U(1,inf)? No...
i feel like an idiot on this problem

I'm not sure that the people who replied in this thread even understood what the problem is. "Interval notation of the continuous line" makes no sense whatsoever.

Were you supposed to write interval notation for the graph you attached?

 

[Torshi]

Yes, writing the continuous line in interval notation. Which if done right you can identify the jumps or moments of discontinuity.

 

[Mark44]

Yes, writing the continuous line in interval notation.

That's not what I said. The goal of the exercise, I believe, was to write the domain of the function in interval notation.

Which if done right you can identify the jumps or moments of discontinuity.

 

[Torshi]

That's not what I said. The goal of the exercise, I believe, was to write the domain of the function in interval notation.

Yes, but it didn't state that specifically in the problem. It simply just said write in interval notation of the continuous line and if there is more then one interval use a union sign. It's fine now though, I figured out the answer and the main reason why I couldn't figure it out was because the site wanted a bracket at the beginning and end, simple mistake which confused me into thinking one of the right answers I plugged in didn't work. I believe the other users knew what my question was because they were guiding me in the right direction.