Help with Determining the Limit of the Sequence Quesiton

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SUMMARY

The discussion focuses on evaluating the limit of the sequence defined by Lim n(2^(1/n)-1) as n approaches infinity. Participants identify that this limit results in an indeterminate form of 0/0, prompting the use of L'Hôpital's Rule. The key solution involves rewriting 2^(1/n) as e^(log(2)/n) and applying the chain rule to differentiate the numerator effectively. This method provides a clear pathway to resolving the limit using calculus techniques.

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Homework Statement



Problem is attached in this post

Homework Equations



Problem is attached in this post


The Attempt at a Solution



Lim n(2^(1/n)-1) as n -> ∞

Lim (2^(1/n)-1)/(1/n) as n -> ∞ -> 0/0 -> Indeterminate Form -> L'Hopital's Rule

However, I can't seem to figure out how to get the derivative of the numerator.
 

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student93 said:

Homework Statement



Problem is attached in this post

Homework Equations



Problem is attached in this post


The Attempt at a Solution



Lim n(2^(1/n)-1) as n -> ∞

Lim (2^(1/n)-1)/(1/n) as n -> ∞ -> 0/0 -> Indeterminate Form -> L'Hopital's Rule

However, I can't seem to figure out how to get the derivative of the numerator.

Write 2^(1/n) as e^(log(2)/n). Now use the chain rule to find the derivative.
 

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