How Do You Calculate Net Inward Force on a Submerged Barrel?

In summary, the conversation is about a cylindrical barrel that falls off a ship and sinks to the bottom of the sea at a depth of 1.61 km. The seawater is assumed to be incompressible, with a density of 1020 kg/m^3 at the bottom of the sea. The pressure inside the barrel is 1.00 atm and its total surface area is 3.50 m^2. The question is to find the net inward force acting on the surface of the barrel at the bottom of the ocean. The formula used is Ptot = Psurface + ρgh, and after calculations, the net force is found to be 4.67 x 10^6 N.
  • #1
xxxzyon
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Help with fluid mechanics!?

Suppose a cylindrical barrel falls off a ship and sinks to the bottom of the sea at a depth of 1.61 km. Assume that the seawater is incompressible, so that its density at the bottom of the sea is the same at the surface :1020 kg/m^3

If the pressure inside the barrel is 1.00 atm (it was sealed at sea level) and the total surface area of the barrel is 3.50 m^2 , find the NET INWARD FORCE acting on the surface of the barrel when it reaches the bottom of the ocean.


For my attempt, I used the formula Ptot = P surface + ρ density of water x g x h.
The total pressure I got was 116 atm, then I plugged this pressure into P = F/A and got a force of 4. 67 x 10^6 N...

I am not sure what I am supposed to be doing first actually, any guidance would be helpful!
 
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  • #2
So it is the surface area of the barrel, times the net pressure (116 - 1)=115 atm, pointing inwards.

Net force = pressure x area.

Your hydrostatic pressure formula looks correct: http://hyperphysics.phy-astr.gsu.edu/hbase/pflu.html
... so double-check your calculations, and you are all done.
 

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