Help with Math Sine Homework in 10 Hours

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Assistance is requested for a math homework assignment involving sine functions, with a 10-hour deadline for completion. The questions include finding values for cos(2x), sin(2x), and sin(x-y), simplifying trigonometric expressions, and proving a tangent identity. A multiple-choice question regarding tan(x+y) is also included. Respondents emphasize the importance of using provided formulas and concepts, while the original poster acknowledges their initial oversight in posting multiple times. The discussion highlights a mix of urgency and casual interaction among participants.
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Can someone help me with my homework?
It would be great if I could get it back within the next 10 hours.
The sooner the better though. Thanks to anyone who can do these for me.
Working out for first 3 questions would be appreciated.
Fourth question only requires multiple choice answer.

1) If sin(x) = 3/5 and sin(y) = 24/25 and, pi/2 < y < x < pi, find the value of:
a) cos(2x)
b) sin(2x)
c) sin(x-y)

2) Simplify
a) [sin(x)/sin(x)] - [cos(3x)/cos(x)]
b) sin(x)cos(x)cos(2x)

3) Prove that tan(pi/4 + x) - tan(pi/4 - x) = 2tan(2x)

4) If tan(x) = 4/3 and tan(y) = 5/12, then the value of tan(x+y) is:
Multiple Choice:
A. sin(2x)
B. cos(2x)
C. sin(4x)
D. 25/24
 
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Next time, please post this only once in one forum, the homework help forum.

When you calculate the sine of an angle, you're dividing the opposite side by the hypotenuse. So, keeping that in mind, here's a little hint:

\sin{x} = \frac{3}{5} = \frac{\textrm{opposite}}{\textrm{hypotenuse}}

So what do you think the opposite and hypotenuse sides might be?

#4 is handled similarly.

#'s 2 and 3 just require you to use a bunch of formulas. I'm certain you were given plenty in your class, so why don't you look at those?

cookiemonster
 
Next time, please post this only once in one forum, the homework help forum.
Sorry bout that, i know, all my fault, sorry.



its more like i am lazy, lol.
i'll get it done, thanks for bossing me, and giving me an incentive to do it now.
lol, ta agen.

Code:
I(laziness) = You/X, X>1
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