- #1

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The question

My attempt

The solution

Why don't I get the same after I take the partial fraction using my calculator? And where does this R(s)=1/s^2 come from

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- Thread starter Huumah
- Start date

- #1

- 28

- 0

The question

My attempt

The solution

Why don't I get the same after I take the partial fraction using my calculator? And where does this R(s)=1/s^2 come from

- #2

gneill

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Remember that a transfer function F(s) is the Laplace domain equivalent of the ratio of the output signal to the input. So if the input is R(s) then:

Y(s) = R(s)*F(s)

The transfer function that you've wrapped in "expand" doesn't appear to correspond to the one given in the problem statement.

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SteamKing

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