- #1

Shay10825

- 336

- 0

Hello everyone! I need help with some problems my physics teacher gave us. The problems I did not show any work for are the ones I have no clue how to do. I would just like a hint or something to get me started (I don't want you to do the whole problem for my because I need to know how to do it myself). I would like to know what I did wrong for the ones I showed work for but I don't want you to do the whole thing. The work is either typed or written. The correct answers are circled or typed. I'm sorry this is so long.

5.) http://img117.exs.cx/img117/6494/number51oa.jpg

7.) http://img117.exs.cx/img117/6541/number72mb.jpg

11.) http://img117.exs.cx/img117/8550/number110wo.jpg

13.) http://img120.exs.cx/img120/6853/number132rd.jpg

14.) http://img120.exs.cx/img120/3610/number14pt12qr.jpg

http://img120.exs.cx/img120/9120/number14pt25rq.jpg

The answer is: A. pi

15.) http://img120.exs.cx/img120/2436/number153bq.jpg

16.) http://img120.exs.cx/img120/3938/number168gf.jpg

The answer is: C. 120

work:

f= 1/(2Lv)

60=1/(6v)

v=.0027

19-22.) I don't know why I scanned 19. I don't need help with 19.

http://img53.exs.cx/img53/1495/number19222qi.jpg

20 work:

f= 1/(2Lv)

so why is the answer .25?

The answer for number 21 is: B. pi

23.)http://img120.exs.cx/img120/6513/number230el.jpg

http://img149.exs.cx/img149/416/number23pt24ij.jpg

The answer is: D. L/8

24 - 27.) http://img149.exs.cx/img149/1576/number24279ia.jpg

For number 24 why is the answer not f= 1/(2Lv)?

30 - 32.) http://img149.exs.cx/img149/2849/number30329am.jpg

How did they get the -10 I number 30? Would you integrate to get the answer? If so how did they get the -10?

For number 31 would I use the formula v=sqrt(T/u)? If so how do I get the values of T and u??

In number 32, I got (400,0) as a point on the graph. So it this why the answer is 4?

34.)http://img149.exs.cx/img149/1332/number343hc.jpg

Is the book wrong for this answer?

Any help would be greatly appreciated.

~Thanks

5.) http://img117.exs.cx/img117/6494/number51oa.jpg

7.) http://img117.exs.cx/img117/6541/number72mb.jpg

11.) http://img117.exs.cx/img117/8550/number110wo.jpg

13.) http://img120.exs.cx/img120/6853/number132rd.jpg

14.) http://img120.exs.cx/img120/3610/number14pt12qr.jpg

http://img120.exs.cx/img120/9120/number14pt25rq.jpg

The answer is: A. pi

15.) http://img120.exs.cx/img120/2436/number153bq.jpg

16.) http://img120.exs.cx/img120/3938/number168gf.jpg

The answer is: C. 120

work:

f= 1/(2Lv)

60=1/(6v)

v=.0027

19-22.) I don't know why I scanned 19. I don't need help with 19.

http://img53.exs.cx/img53/1495/number19222qi.jpg

20 work:

f= 1/(2Lv)

so why is the answer .25?

The answer for number 21 is: B. pi

23.)http://img120.exs.cx/img120/6513/number230el.jpg

http://img149.exs.cx/img149/416/number23pt24ij.jpg

The answer is: D. L/8

24 - 27.) http://img149.exs.cx/img149/1576/number24279ia.jpg

For number 24 why is the answer not f= 1/(2Lv)?

30 - 32.) http://img149.exs.cx/img149/2849/number30329am.jpg

How did they get the -10 I number 30? Would you integrate to get the answer? If so how did they get the -10?

For number 31 would I use the formula v=sqrt(T/u)? If so how do I get the values of T and u??

In number 32, I got (400,0) as a point on the graph. So it this why the answer is 4?

34.)http://img149.exs.cx/img149/1332/number343hc.jpg

Is the book wrong for this answer?

Any help would be greatly appreciated.

~Thanks

Last edited: