Help with products of reactions

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The discussion revolves around the chemical reactions involving zinc sulfate and sodium hypochlorite, manganese(II) sulfate with sodium periodate, and the behavior of various phosphates in ammonium molybdate solutions. Participants clarify that the reaction of ZnSO4 and NaClO likely produces ClO3- and Cl- due to the disproportionation of ClO-. For the manganese sulfate and sodium periodate reaction, a proposed equation suggests the formation of permanganic acid and sodium iodate, though balancing issues are noted. Additionally, the reactions of NaH2PO2, Na2HPO3, and Na2HPO4 with ammonium molybdate and sulfuric acid yield distinct color changes and precipitates, indicating complex interactions. Overall, the thread highlights the intricacies of these chemical reactions and the need for accurate balancing in reaction equations.
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Hello; thank you in advance for anyone who would like to help:
I am looking for the products of these reactions:

ZnSO4 + NaClO -->
I thought it was just a double displacement, which would make my reaction equation:
Zn(ClO)2 + Na2SO4
but a test with silver nitrate was positive for Cl- ions, so that has to be somewhere in the products. Is it possible that the ClO oxidizes the sulfate or something; i know that sulfite becomes oxidized to sulfate, but I am kind of stuck.

also:


what happens when manganese (II) sulfate is added to a solution of aqueous sodium periodate (meta) in a bit of acid (phosphoric). A pink colour was observed, but what is the reaction equation?
I was thinking:
MnSO4 + 2 NaIO4 --> Mn(IO4)2 (is that pink) + Na2SO4

Lastly, what happens to NaH2PO2, Na2HPO3, and Na2HPO4, when they are added to an ammonium molybdate solution, heated, and then have 4M sulfuric acid added. (ie what are the reacton equations). The observed products were blue liquid, white precipitate, and yellow precipitate respectively. I keep finding conflicting info as to the formula for molybdate; so I am kind of stumped.

Thanks everyone
 
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1st - I can't see any obvious reaction, however, I will check whether there were no Cl- ions in substrates. Hypochlorates hydrolyse slowly producing Cl- and O2.

2nd - IMHO pink stands for MnO4-.


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Thank you; for the first one, I also found that ClO- disproportionates in solution giving ClO3- and Cl-

I have also worked out what I think is the periodate/manganese sulfate reaction:

2MnSO4 + NaIO4 + 3 H20 --> 2 HMnO4 + NaIO3 + 2 H2SO4; does this look alright?
 
pariswhitney said:
Thank you; for the first one, I also found that ClO- disproportionates in solution giving ClO3- and Cl-

Never heard about it. O2 (or more precisely atomic O) is the reactive substance in the bleach.

2MnSO4 + NaIO4 + 3 H20 --> 2 HMnO4 + NaIO3 + 2 H2SO4; does this look alright?

Oxygen is not balanced properly.


Chemical calculators for labs and education
BATE - pH calculations, titration curves, hydrolisis
 
I also found that ClO- disproportionates in solution giving ClO3- and Cl-

I found this in a book called Vogel's Textbook of Macro and Semimicro Qualitative Inorganic Analysis.

Oxygen is not balanced properly.
Oops. I have 5's in front of the NaIO4 and the NaIO3
 
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