HELP with question, I can't come up with the answer.

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The discussion centers on calculating the collision point of two knights on horseback starting 88.0 meters apart, with Horse A accelerating at 0.300 m/s² and Horse B at 0.200 m/s². The relevant equations for this problem are d = 1/2at² + v₀t and v = v₀ + at, where initial velocity (v₀) is zero for both horses. The solution requires determining the time it takes for both horses to meet, which can be derived from their respective accelerations and initial positions.

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I have a problem and I can't solve it. Do I have enough info?

Two knights on horseback start from rest 88.0m apart and ride directly toward each other to do battle. Horse A accelleration has a magnitude of 0.300 m/s^2, while Horse B has a magnitude of 0.200 m/s^2.

Relative to Horse A's starting proint, where do the horses collide?

I am not sure what to do here.
Can you tell me what formula or formulas I need to use to figure this out. Just a work question and have no clue. Do I have enough info tho??


Please let me know ASAP, thanks for looking and helping if you do.
Joanne

This is what I came up with, but not sure, still can't get the answer. of 52.8m
 
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This one appears to not have enough knowns to deal with, but look closer.

Your equations would be:

d = 1/2at^2+vot

v = vo + at

If the riders start at from 0, that gives you vo=0. Does that help?
 

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