Help with related rates problem

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Homework Statement



A 16-ft ladder is sliding down a wall at a rate of 4 ft/sec. Find the velocity of the top of the ladder at t=s if the bottom is 5ft from the wall at t=0.

Homework Equations



It's a related rates problem.
Not sure how I'm supposed to incorporate t=s into the problem, or if I'm supposed to solve for dx/dt or dy/dt.
Or if I'm even on the right track.

The Attempt at a Solution



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Last edited:
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Thought I would add, this is a similar problem that was in my notes, but there are differences between the two problems such as the direction the rate of the ladder is sliding and I have to find it at t=s.

16bmzie.jpg
 
This is due in a few hours I hope I get a response by then.
 
Just turned it in, thanks for the help everybody :)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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