Help with solving two unknowns simultaneously? (physics)

[ilovecarter]

A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 566 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope to the left and to the right of the mountain climber. (From the figure α = 65.5° and β = 83.0°.)
Equations:
EFx= 0 since she is at equilibrium
EFy= 0 since she is at equilibrium

I got up to the part where
EFx= Tr Sin 83 -TL Sin 65.5 = 0 and I get Tr = TL Sin 65.5/ Sin 83
EFy = Tr cos 83 + TL cos 65.5 - W = 0

now when you put the two together we get

( TL sin 65.5/ sin 83 ) cos 83 + TL cos 65.5 - w = 0

this is the part where I'm stuck. I don't how they solved for the TL and w together. Do you? Thanks alot!

 

[Delphi51]

You know w - it is 566.
The angles are with respect to the vertical, right?

 

[ilovecarter]

Oh, But still, how do I solve for TL then?

here is the image of the problem
http://i928.photobucket.com/albums/ad123/pinkinkie24/phy.jpg

and thanks for replying!

 

[Delphi51]

Factor TL out of the two terms, move w to the other side and put in its number. Divide both sides by whatever TL is multiplied by.

 

[ilovecarter]

OH! I see now... Thank you very much!

 

[ilovecarter]

I got
TL = 1075 N
TR= 985.6

in case anyone also needs help with this.

 

[Delphi51]

Most welcome!