Help with testing the convergence of a series

bolzano
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Hi i have to show that the series 1+2r+r2+2r3+r4+2r5+... converges for r=\frac{2}{3} and diverges for r=\frac{4}{3} using the nth root test.

The sequence \sqrt[n]{a_{n}}comes a bit complicated so i was wondering if I can remove the 1st term a1=1 and show that 2r+r2+2r3+r4+2r5+... converges, using the test of course.

Am i doing something wrong?

Thanks :)
 
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Yes you can remove any finite number of terms and not change whether the series converges or not.
 
So (\sqrt[n]{a_{n}})=2r,r,\sqrt[3]{2}r,r,\sqrt[5]{2}r,... which converges to r right? :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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