Help with velocity vector and friction questions

AI Thread Summary
The discussion revolves around solving physics problems related to velocity vectors and friction. The first problem involves deriving the minimum stopping distance for a car, which is expressed as v^2 / (2 * coefficient of friction * g), emphasizing the relationship between speed, friction, and gravity. The second problem focuses on a ball rolling off stairs, requiring an analysis of its parabolic trajectory to determine which step it will hit first. Participants highlight the need for a parametric approach to solve these problems, particularly in calculating deceleration due to friction without specific values. The conversation underscores the importance of understanding the underlying physics concepts to tackle these types of questions effectively.
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I can't quite get an answer for these damn questions. It feels like there is information missing.

1. Show that the minimum stopping distance for a car traveling at speed v is equal to v^2 / 2*coefficient of friction*g, where the coefficient of static friction is between tires and the road and g is acceleration due to gravity.

2. A ball rolls off the top of a stairway with a horizontal velocity of magnitude 1.5m/s. The steps are 20 cm high and 20 cm wide. Which step will the ball hit first?
 
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1. Use this formula:
vf2 = v02 + 2ax
The distance is x, v0 is v and a is the car's deceleration caused by friction.

2. Let's create an axes system of X and Y, with the origin placed in the ball's inital position (top of stairs). The ball is traveling in a parabola. By analyzing the graph I attached, you can see that as soon as the ball's vertical displacement is bigger than or equal to the horizontal displacement, the ball will hit a step. (This is because the width and height of each step is equal. If this weren't the case, things would have been a bit more complicated.) So let's write the expressions for each displacement:

Δx = vt
Δy = gt2/2

Now solve this for t:

Δx = Δy
vt = gt2/2

One of the solutions is t = 0, because when the ball is first thrown it is on a step! So that's correct. The second solution is t = 2v/g. Now go back to the Δx expression and find how much the ball has managed to travel before hitting the step. For example, if the ball traveled 0.46 meters it means that it hit the 3rd step (if we don't count the step the ball was thrown from).
 

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Chen said:
1. Use this formula:
vf2 = v02 + 2ax
The distance is x, v0 is v and a is the car's deceleration caused by friction.

QUOTE]

I tried but I do not have any values for those variables. I don't get how I would go about doing this question.
 
You don't need values, this is a parametric question. Find a (using what you know about the friction force) and then find the expression for x.
 
i still can't get a. please give me a little more info
 
I got a=-232.4/v^2. But I don't know where to go from there
 
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