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Hi, I need some help with a homework problem invovling acceleration

  1. Dec 7, 2006 #1
    1. The problem statement, all variables and given/known data
    What is the acceleration of your car?

    Time Velocity[ms]
    1 8.8
    2 12.82
    3 16.25
    4 20.46
    5 24.22
    6 28.09
    7 31.77
    8 35.24
    9 39.32
    10 42.37
    11 44.61
    12 46.63
    13 49.01
    14 50.53
    15 52.1
    16 52.32
    17 53.6
    18 53.44
    19 53.74
    20 53.25

    [​IMG]


    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Dec 7, 2006 #2
    I really just don't know where to start, is there an equation I need to use or is this much more complicated?
     
  4. Dec 7, 2006 #3

    Kurdt

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    Staff Emeritus
    Science Advisor
    Gold Member

    The definition of acceleration is the rate of change of velocity with time. What you need to do is find out how much the speed changed and in what time, then:

    [tex] a= \frac{\Delta v}{t}[/tex]
     
  5. Dec 7, 2006 #4
    (53.25 - 8.8) = 44.45

    a = (44.45) / 20s

    a = 2.2225 m/s

    Is this right?
     
  6. Dec 7, 2006 #5

    radou

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    Homework Helper

    What's with the function in the upper right edge v(t) = 3.6688 t + 5.6189 ?
     
  7. Dec 7, 2006 #6
    That's just the slope of the trendline for the increasing part of the graph. He told us in class we had to show it.
     
  8. Dec 7, 2006 #7

    cristo

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    Staff Emeritus
    Science Advisor

    Ok, so from above [tex] a= \frac{\Delta v}{t}[/tex] , or to put it another way, a is the gradient of the graph of v against t. Given your trendline, in the form y=mx+c, how can you read off the gradient?
     
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