High energy proton beam collimation

1Keenan
Messages
99
Reaction score
4
Hi all,

my question is not strictly related with physics and I don't know if it is the right section.
Anyway I have a problem with a collimator: I need 100micron (or maybe smaller) collimator, but the high energy (60-70 MeV) of the beam need a material which is at last 5mm thick, (tungsten for example).
My problem is that I cannot find any workshop able to drill such a small hole on the thickness I need.
I know I could use a stack of smaller collimators, but who drills the hole do not assemble the stack and I'm quite sure the result could be quite poor...
Do you know someone who can solve my problem
 
Physics news on Phys.org
You could try to make two parts (like "left" / "right"), and get the hole as result of their combination.
Or ask existing accelerator projects how they built their collimators.

high energy (60-70 MeV)
:wink:
 
mfb said:
You could try to make two parts (like "left" / "right"), and get the hole as result of their combination.
Or ask existing accelerator projects how they built their collimators.


:wink:

the left/right thing could be a solution, but anyway it works on thinner materials, I would need the stack anyway.

Collimators used in accelerator projects ar not so small... :(
 

Thread 'Toponium Discovered'

Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
View full post »

Thread 'Dirac-Delta from Normalization of Continuous Eigenfunctions'

I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
View full post »

Similar threads

A Influence on Neutron spectrum due to energy loss of beam
Replies
8
Views
2K
A How Can I Create a Small Pinhole Collimator for High Energy Particles?
Replies
7
Views
1K
A Photons per unit of Energy in Cherenkov radiation?
Replies
1
Views
2K
I New ultra-high energy Neutrino
Replies
2
Views
1K
I ZnS:Ag Detects 10 keV Protons in High Vacuum
Replies
3
Views
1K
Making a 50 um collimated beam on a budget
Replies
5
Views
4K
Would a transversal beam of electrons increase the energy collision in the LHC?
Replies
8
Views
3K
I Why not deuterium-proton fusion?
Replies
13
Views
6K
Deflecting high energy proton beam
Replies
1
Views
2K
I Gamma radiation, photon energies and wavelength question
Replies
4
Views
2K

Hot Threads

Recent Insights

Back
Top