Finding the Right Normalization Constant for Gaussian Integrals

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Hello I have tried gaussian integrals does gaussian integrals have this general form formula? if not then weather i do integration by parts or what just needed a hint to solve it correctly
 

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Hello Core, :welcome:

The template is there for a reason, don't erase it but use it; it will be to your benefit.

What is the question ? and what is the relationship between your first line and the second ?
 
I want to say in the pic I have tried many things here should I show the steps I tried?? just want a hint that how to correctly start this nothing more weather I substitute or use gaussian integral formula for expomentional that is sqrt(pie/a) then do integration by parts??
 
My point is it seems you are trying to normalize the wave function $$\Psi(x,t) = A\, e^{-x^2/a^2} e^{-i\omega t} \sin kx $$ on the first line.
But the second line does not reflect that ( it says ##\ \sin (2kx) \ ## instead of ##\ \sin^2 (kx) \ ## ).

So :
BvU said:
What is the question ? and what is the relationship between your first line and the second ?
 
yes yes it is sin^2(kx) we can use 1-cos2(x)/2 formula here
 
but that nasty exponential how to handle that
 
it is liboff problem 3.15 I have found <p> that is zero but I stuck at A?
 
these steps I have tried now where is mistake??
 

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Now see here in this formula list there no formula for x^2 that's why I am stuck at this step needed a hint
 

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  • #10
how to integrate E^x^2/a^2 sinkx
 
  • #11
core1985 said:
yes yes it is sin^2(kx) we can use 1-cos2(x)/2 formula here
For the latter expression, if you mean ##\frac{1 - \cos^2(x)}2##, use parentheses around the terms in the numerator. What you wrote means ##1 - \frac{\cos(2x)}2##. In any case, ##\sin^2(kx) \ne \frac{1 - \cos(2x)}{2}##. You have to consider that k mulitplier.
 
  • #12
thanks I am new to this website
 
  • #13
Maybe you want to check out number 6 here ?

Otherwise there is CRC handbook of chemistry and physics, or Abramowitz (7.4.6)
 
  • #14
so if I use number 6 then can I change limits to 0 to infinity multiplied by 2 then It can be applied ?
 
  • #15
one thing more can I change sin(kx) into exponentionals and then try to solve will it work or not??
 
  • #16
core1985 said:
so if I use number 6 then can I change limits to 0 to infinity multiplied by 2 then It can be applied ?
IF the function is even (##\ f(x) = f(-x)\ ##) then yes.
core1985 said:
one thing more can I change sin(kx) into exponentionals and then try to solve will it work or not??
You can give it a try... :rolleyes:
 
  • #17
what do you suggest now changing sin to exponential using euler formula or use this
 
  • #18
but cos(kx) is even ?? so I can use this to solve this nasty integral
 
  • #19
ok I am solving it by both methods and will tell you what I got
 
  • #20
core1985 said:
but cos(kx) is even ?? so I can use this to solve this nasty integral
Yes you can
core1985 said:
what do you suggest now changing sin to exponential using euler formula or use this
That would be the idea. But it doesn't look clean and quick to me, such a complex exponential...

After all, integrating ##\ e^{-x^2}\ ## alone already requires ingenious mathematical manipulating...
 
  • #21
ok then I use cos formula but can normalization have ? e term? according to the formula number 6 means I can write exponential in normalization
 
  • #22
The normalization process is to determine your ##A## such that ##\displaystyle \int \Psi(x,t)^* \Psi(x,t) \ = 1 ##. The result of the indefinite integral is basically just a number.
 

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