Hitting a billiard ball h above centerline

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The discussion focuses on calculating the height h above the centerline where a billiard ball is struck to achieve a final speed of 9vo/7 after being given an initial speed vo. The user attempts to derive the relationship using equations involving torque and angular acceleration, but encounters difficulties with the variable ω0. They reference a specific problem from MIT's course materials for additional context. The goal is to demonstrate that h equals 4R/5, where R is the ball's radius. The conversation highlights challenges in applying rotational dynamics to the problem.
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Homework Statement



A billiard ball, initially at rest, is given a sharp impulse by a cue. the cue is held horizontally a distance h above the center line. the ball leaves the cue with a speed vo, and because of its "forward English", eventually acquires a final speed of 9vo/7. Show that h=4R/5, where R is the radius of the ball.

Homework Equations


The Attempt at a Solution


I've tried using FRsin(θ)=Iα and coming up with h = (2/5)R^2(α/a). Then using the impulse equation a = v0/Δt and α= ω0/t i got h=(2/5)R^2(ω0/v0). The thing is I keep getting wrong and contradictory answers about ω0.
 
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