Hmmmm how to find the taylor series based @ b for this function?

[myusernameis]

Homework Statement

1/(4x-5) - z/(3x-2) based @ 0, answers are in those z things.. sigma

Homework Equations

i think we use sigma of e^x, but idk how...

The Attempt at a Solution

since tayor sereis of e^x is like 1/x, do i plug 4x-5 in?

thanks

 

[Dick]

I really don't understand that. Is that a function of two variables, x and z?

 

[myusernameis]

I really don't understand that. Is that a function of two variables, x and z?

haha... no i don't know how "z" got in there... the question is asking us to find the taylor series by using like e^x, sin x, or 1/(1-x) taylor series...
idk if that's making sense ...

 

[Dick]

Then use things like 1/(1-x)=1+x+x^2+... You can expand inverse linear functions like 1/(ax+b) as a power series.

 

[Mark44]

haha... no i don't know how "z" got in there... the question is asking us to find the taylor series by using like e^x, sin x, or 1/(1-x) taylor series...
idk if that's making sense ...

You didn't ask my opinion, but I'll give it to you anyway, for free. I think you're in a class that's way over your head. You don't seem to be able to tell us what the problem is, and I don't believe you have any idea what a Taylor's series is. Much of what you've written makes no sense ("sigma of e^x", "answers are in those z things ... sigma").

Mark

 

[myusernameis]

You didn't ask my opinion, but I'll give it to you anyway, for free. I think you're in a class that's way over your head.
Mark

haha :D you are kind of right... i learned this stuff but I'm trying to refresh my memory... and as for the "z things" i was just trying to be stupid...
thanks for the advice tho... and i do know what a taylor series is.. i think.
(is it to approximate another function at a point?)
i think that's what it is.edit: lol ", for free." XD

 

[myusernameis]

Then use things like 1/(1-x)=1+x+x^2+... You can expand inverse linear functions like 1/(ax+b) as a power series.

ahh thanks!