- #106
mtworkowski@o
- 213
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who did he say stunk? I think he was OK.
icanbuildit said:I lost three fingers building one of my kayaks...
Mech_Engineer said:If you propose to use compressed air for a power source, you need to carry it on-board. Otherwise you'll need to carry your required energy to compress the gas on-board in some other form, like gasoline.
This isn't sounding good. You're saying you use the kinetic energy from the blades to drive a compressor that pumps air to spin the blades, so at most all this thing could do is spin the blades for a little bit until they run out of kinetic energy (you're neglecting external air drag on the blades also, probably one of the largest factors on a helicopter rotor).
With 5 horsepower of input, that will be your maximum output as well. The point of a helicopter's engine is to put out enough power to create a downward flow of air that in turn creates a thrust in the opposite direction. Moving all of that air takes a lot of energy, and since your special blades aren't "creating" any energy no matter how complex the rotary vane compressor approach is, they're just spinning around and will completely dependent on additional power input if they need to lift something.
Being "very close to a perpetual motion machine" is probably not a good thing... To answer your question the only fundamental efficiency that all machines must live by is that their efficiency will be less than 100%. For a machine to continue moving indefinitely, it must have a power input that is equal to all losses in the system.
Your problem is that you're thinking of the rotor as the system, where all it needs to do is keep spinning. In fact the rotor is one part of a helicopter as a system, and the rotational kinetic energy stored in the rotor is small compared to the energy required to keep the helicopter aloft for say 5 minutes.
harpreet singh said:I am working on another problem if u can help me in that,
I have to calculate strain energy of a clamped circular plate with governing equation in polar coordinates. The plate is loaded uniformly. And deflection is in transverse directon to the plate. Can u help me out in finding the required equations and the values of the coefficients of D matrix involved in it...
RonL said:For everyone that thinks we need 40 horsepower to fly a helicopter, may I suggest we start here, and work up the power ladder to the point where height, and duration becomes worthwhile.
The flight reached an altitude of 8 inches for a period of 8 seconds. The machine was not stabilized. Later attempts with a stabilized machine were considered but not accomplished.
mtworkowski@o said:Hensen and Sringfellow flew an elastic powered machine 100 meters before it encountered a stationary object.
http://www.cavalrypilot.com/fm1-514/Ch2.htmCavalryPilot.com said:Ground Effect
When hovering near ground or water surfaces at a height no more than one-half of the rotor diameter, the helicopter encounters a condition referred to as ground effect. This condition is more pronounced nearer the ground. Helicopter operations within ground effect are more efficient due to reduction of the rotor tip vortex and the flattening out of the rotor downwash. The benefit of ground effect is lower blade angle of attack, which results in a reduction of power requirements for a given load.
"Heh heh heh heh HAH HAH model planes HAH HAH He builds model planes! AH HAH HAH HA HAH"mtworkowski@o said:It's line from the 1965 film "Flight of the Phoenix". Hardy Kruger is very convincing as an aeronautical engineer.
mtworkowski@o said:Mech Engineer,
That website was very informative and easy to read.
DaveC426913 said:"Heh heh heh heh HAH HAH model planes HAH HAH He builds model planes! AH HAH HAH HA HAH"
(I have the 1:72 scale Flying Boxcar model kit still in its shrinkwrapping waiting for the day when I build the diorama of the film.)
FredGarvin said:For a pure hover, more power is required than what a fixed wing will need for a rolling take off. The numbers won't lie if you apply them correctly.
RonL said:While you guys are calculating, I have been watching my lawn sprinkler and thinking about how air would spin it, if it were to be hooked to a air hose.
Now concerning a very light machine (almost anything can be done)
Without considering the source of air, but only the results, how much volume and pressure would produce thrust enough to lift 400 pounds, if there are two counter rotating rotors, seventeen feet in diameter ? (4 tips discharging air, pushing the blades in a forward direction).
I know there are many other factors involved, and speed of the rotors will depend mostly on pressure, but it seems that larger volume, lower pressure will be easier to produce.
Any help with the calculations ??
Ron
VortechOnline said:G-1 Details http://www.vortechonline.com/g1/
Length. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 12 ft
Width . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5.7 ft
Height. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5½ ft
Main rotor diameter. . . . . . . . . . . . . . . . . . . . . . . 12 ft
Tail rotor diameter. . . . . . . . . . . . . . . . . . . . . . . . 2 ft
Empty weight. . . . . . . . . . . . . . . . . . . . . . . . . . . 150 lbs
Gross weight . . . . . . . . . . . . . . . . . . . . . . . . . . . 420 lbs
Useful payload . . . . . . . . . . . . . . . . . . . . . . . . . . 270 lbs
Engine (typical) . . . . . . . . . . . . Kawasaki or Rotax, 40+ hp
Fuel capacity . . . . . . . . . . . . . . . . . . . . . . . . . . . 5 gals
Fuel consumption . . . . . . . . . . . . . . . . . . . . . . . . 4 gals/hour
Speed (max.). . . . . . . . . . . . . . . . . . . . . . . . . . . 80 mph
Altitude (max.) . . . . . . . . . . . . . . . . . . . . . . . . . 10,000 ft asi
http://en.wikipedia.org/wiki/HelicopterWikipedia.com said:Tip jets
Another single main rotor configuration without a tail rotor is the tip jet rotor, where the main rotor is not driven by the mast, but from nozzles on the tip of the rotor blade; which are either pressurized from a fuselage-mounted gas turbine or have their own turbojet, ramjet or rocket thrusters. Although this method is simple and eliminates torque, the prototypes that have been built are less fuel efficient than conventional helicopters and produce more noise. One example, the Percival P.74, was not even able to leave the ground, and the Hiller YH-32 Hornet had good lifting capability but was otherwise poor. The Fairey Jet Gyrodyne and 40-seat Fairey Rotodyne flew very well indeed. Possibly the most unusual was the rocket tipped Rotary Rocket Roton ATV. None have made it into production.
Dragonich said:Hi Guys,
I'm new - I just joined about 30 seconds ago, after seeing this page. Me and my friend (though pretty much just me) are working on making our own aircraft. I'm covering helicopters, and he's meant to be covering fixed-wings. Anywayz, I've been testing out some very basic fuel (bi-carbonated soda+vinegar) but I'm trying to make it be released slowly, as right now it's going out in less than 2 seconds. I've tried a couple of thing but they've failed. So, my question to anyone who can be bother answering this (thanks if you do), how could I make bi-carbonated soda+vinegar be released slowly?
Dragonich said:Hi Guys,
I'm new - I just joined about 30 seconds ago, after seeing this page. Me and my friend (though pretty much just me) are working on making our own aircraft. I'm covering helicopters, and he's meant to be covering fixed-wings. Anywayz, I've been testing out some very basic fuel (bi-carbonated soda+vinegar) but I'm trying to make it be released slowly, as right now it's going out in less than 2 seconds. I've tried a couple of thing but they've failed. So, my question to anyone who can be bother answering this (thanks if you do), how could I make bi-carbonated soda+vinegar be released slowly?
That will release the same amount of gas, just at a higher pressure/velocity. What you want to do is limit the rate at which the fuel components mix before formng the gas.mtworkowski@o said:I'm no kind of scientist but I would think that the pressure vessel should have a very small hole to release the gas.
DaveC426913 said:That will release the same amount of gas, just at a higher pressure/velocity. What you want to do is limit the rate at which the fuel components mix before formng the gas.
I have no experience in this area but it seems to me that one way to do that is to limit the amount of area whereon the powder and liquid can mix. I'm thinkin' don't bother with a big tank o bi-carb soda and a big tank o vinegar and small dispensing devices, that you lay it out so that the vinegar run through down a tube that's got powder in it. This restricts the rate at which they can come into contact.
(If you examine how the solid boosters on the shuttle work, you'll see that there's no throttling mechanism for fuel/oxy mix at all; there is simply a carefully arranged surface area of solid fuel that only let's a certain amount of oxy react with the exposed solid fuel.)
That's right. The cool thing about solid props is that the arrangement of the propellants in the solid stage are designed to try to maintain the same surface area during the entire burn process.DaveC426913 said:That will release the same amount of gas, just at a higher pressure/velocity. What you want to do is limit the rate at which the fuel components mix before formng the gas.
I have no experience in this area but it seems to me that one way to do that is to limit the amount of area whereon the powder and liquid can mix. I'm thinkin' don't bother with a big tank o bi-carb soda and a big tank o vinegar and small dispensing devices, that you lay it out so that the vinegar run through down a tube that's got powder in it. This restricts the rate at which they can come into contact.
(If you examine how the solid boosters on the shuttle work, you'll see that there's no throttling mechanism for fuel/oxy mix at all; there is simply a carefully arranged surface area of solid fuel that only let's a certain amount of oxy react with the exposed solid fuel.)