Homeomorphism of Rings: Proving Existence for Prime Numbers p and q

TimNguyen
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Let p,q be two prime numbers. Prove that there exists a homeomorphism of rings such that f([1]_p)=[1]_q from Z_p[X] into Z_q[X] if and only if p=q.

I believe that the converse of the statement is trivial but the implication seems to be obvious? I really don't know what there really is to prove in this.
 
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I think you mean homomorphism? Certainly, the converse is trivial but if the implication is obvious, then what is the proof? Note, that the statement that there exists a homomoprhism of rings such that f(1) = 1 is the statement that there exists a homomorphism of rings such that f(1) = 1.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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