Homework Help: Find Power Used by 60 Watt Bulb Connected to 120VAC

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A 60 Watt incandescent bulb with a resistance of 240 ohms connected to a 120 VAC source uses 60 Watts of power. The equation P = V^2/R confirms this, as substituting the values yields the expected result. The discussion highlights the importance of using RMS voltage instead of peak voltage for calculating average power. Despite initial confusion, the consensus is that the answer remains 60 Watts. The question may serve as a test of students' attention to detail.
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Sorry if this is the wrong forum, it's a homework question I'm stuck on, though. :|

The question is that if a 60 Watt bulb has a hot resistance of 240 ohms when it's connected to a 120 VAC source, how much power is the bulb using?

Now I'm not exactly sure what equation to use, I thought it would be P = V squared divided by R? That just gives me 60 W, though. What equation do I use to get the power used?
 
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looks right to me. power being used is V^2/R = 60W.

Did you post the question exactly as it is written?
 
Yah, that's pretty much how it's written. Here's the exact question:

A 60 Watt incandescent bulb has a "hot" resistance of 240 ohms when connected to a 120 VACrms source. How much power is the light bulb using?

So...the answer is 60 Watts, then? Is it a trick question? o_O
 
Oh wait... in order to get average power, you need to use rms voltage, not peak voltage.

v_{rms} = \frac{v_{peak}}{\sqrt{2}}

then use average power = \frac{(v_{rms})^2}{r}
 
Oh crap. sorry again... so they give you 120V rms not 120peak...

So then 60W is the answer. hmmm... strange question...
 
Maybe my teacher is checking to see if we're paying attention. :P
 

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