Homework help: work done on gas (Basic thermodynamics)

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msaleh87
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Homework Statement



A fixed mass of an ideal gas undergoes a cycle PQRP of changes as shown in the following figure:

35a4p5f.png


Some energy changes during the cycle PQRP are shown in the following figure

vx0uti.png


Complete the Figure

Homework Equations



Find the work done on gas from R to P

The Attempt at a Solution



I know the work is the are under the curve from R to P
But how to find it
I approximated the curve to a straight line
but I am not sure

Thanks
 
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Just find the area of one square and then just count the number squares under the curve.

Which is the simplest way to get an approximate answer. Otherwise you'd need to integrate and whatnot.
 
I think I have found the solution
It is not by counting squares
 
Have you taken the work done to be the area between the curve and the left hand axis (VOLUME)? This is what it should be !
This graoh has been drawn with V on the vertical axis and P on the horizontal axis. It is usually drawn the other way round... makes a difference to the area you work out.
 
msaleh87 said:
I think I have found the solution
It is not by counting squares

Alternatively you could apply the first law for a cycle which is ∑W = ∑Q (if I remember correctly)
 
ok

firstly note that the axis are reversed "X axis is pressure and Y axis is volume"

the problem is in the last row in the table
how to find the work "the area" under the curved path RP

Appluing the second law but for the whole process:
ΔU=W+Q

here ΔU=o for the whole process
Q= -600+720+480 "for the whole process"
now W= 600

so this is the area enclosed by the closed path "because we applied the 2nd law to the whole process"

now adding the are under PQ to this area, we get the area under the curve RP