Homogeneity holds but additivity does not. I'm stuck

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    Homogeneity Stuck
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Homework Statement


Give an example of a function f:R^2 -> R such that f(av) = a(f(v)) for all a in R and all v in R^2 but f is not linear.


Homework Equations


f(v + w) = f(v) + f(w) (Additivity)


The Attempt at a Solution



I really can't think of a function that will satisfy these properties. I know that for this to work, homogeneity must hold but additivity must not. I tried several functions, but none worked. Any hints? Thanks.
 
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How about f((x,y))=x^(1/3)*y^(2/3)?
 
Dick said:
How about f((x,y))=x^(1/3)*y^(2/3)?

Thanks! I see how you came up with that now. I tried f((x, y)) = x^2 + y^2 but the first property didn't hold since a changed. :rolleyes: Your function fixes that issue. Thanks again for the help.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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