Hooke's Law and Force in a Slingshot

In summary, a rock is placed in a slingshot and the rubber band is stretched. The force of the rubber band on the rock is shown by the graph in the figure. The rubber band obeys Hooke's law and the spring constant is k. The rubber band is stretched 29cm and then released. What is the speed of the rock?
  • #1
mcnealymt
35
0

Homework Statement


A 46g rock is placed in a slingshot and the rubber band is stretched. The force of the rubber band on the rock is shown by the graph in the figure(Figure 1) .

http://session.masteringphysics.com/problemAsset/1073689/4/10.P37.jpg


a)Is the rubber band stretched to the right or to the left?
b)Does this rubber band obey Hooke's law?
c)What is the rubber band’s spring constant k?
d)The rubber band is stretched 29cm and then released. What is the speed of the rock?

Homework Equations



Fsp= -kΔx

The Attempt at a Solution



a) Left because the displacement is negative and therefore the Fsp must be positive?
b) Yes, it obeys Hooke's Law because as the displacement increases, the amount of force does?
c) Isn't it just the slope of the given graph?
d) Honestly not sure where to begin.
 
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  • #2
mcnealymt said:
a)Is the rubber band stretched to the right or to the left?
b)Does this rubber band obey Hooke's law?
c)What is the rubber band’s spring constant k?
d)The rubber band is stretched 29cm and then released. What is the speed of the rock?

The Attempt at a Solution



a) Left because the displacement is negative and therefore the Fsp must be positive?
b) Yes, it obeys Hooke's Law because as the displacement increases, the amount of force does?
c) Isn't it just the slope of the given graph?
d) Honestly not sure where to begin.

a) and b) are correct but b) can be amended as " the force is proportional to the displacement and in opposition to it and hence obeys the law".

For c) yes it is the slope.

For d) are you aware of the expression for energy stored in the band as a function of the stretch(x)? If yes, try conservation of energy. If no, try deriving the expression using
Energy stored=∫F.dx for the band and then use conservation of energy.
 
  • #3
Alright, thank you. It turns out I forgot to convert the mass to kg.

This is what I got:

Spring Potential Energy= Kinetic Energy
Us (initial)=KE (Final)
.5kx^2= .5mv^2

V= Square root of ( K*X/m)

k= spring constant
X= change in displacement
m= mass of the rock
 
  • #4
mcnealymt said:
V= Square root of ( K*X/m)

You mean square root of Square root of ( K*(X^2)/m) right? That was unintentional on your part I guess.

Anyway, Enjoy Physics.:smile:
 
  • #5
Lol, fail on my part... thanks Sunil Simha.
 

What is Hooke's Law?

Hooke's Law is a principle in physics that describes the relationship between force and displacement for a spring or elastic material. It states that the force applied to an elastic material is directly proportional to the displacement caused by that force.

Who discovered Hooke's Law?

Hooke's Law was discovered by English scientist Robert Hooke in the 17th century.

How is Hooke's Law expressed mathematically?

Hooke's Law can be expressed mathematically as F = -kx, where F is the force applied to the material, k is the spring constant, and x is the displacement from the material's equilibrium position.

What is the significance of Hooke's Law?

Hooke's Law is significant because it provides a simple and accurate way to calculate the force needed to stretch or compress an elastic material. It is also used in many real-world applications, such as in the design of springs, shock absorbers, and other elastic components.

Are there any limitations to Hooke's Law?

While Hooke's Law is a useful approximation for many materials, it does have some limitations. It only applies to materials that exhibit elastic behavior, and it is not accurate for large deformations or very stiff materials. Additionally, Hooke's Law assumes that the material will return to its original shape when the force is removed, which may not always be the case.

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