- #26
- 275
- 2
its just like solving for the zero's (x-intercepts) of any polynomial equation.
how can you get 2cosx*(sinx + 1) to = 0. either cosx = 0 or sinx + 1 = 0. what values of x give you those? and here we see the 2 solutions (actually infinite solutions, but for practical purposes, 2)
how can you get 2cosx*(sinx + 1) to = 0. either cosx = 0 or sinx + 1 = 0. what values of x give you those? and here we see the 2 solutions (actually infinite solutions, but for practical purposes, 2)