How Big is the Balloon When Helium Tank Pressure Drops?

gabriel5
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Homework Statement


Helium in a steel tank is at 250kPa, 300K with a volume of .1m^3. It is used to fill a balloon. When the pressure drops to 150kPa, the flow of helium stops by itself. If all the helium is still at 300k, how big balloon is produced?

Homework Equations


I used the ideal gas law PV=mRT


The Attempt at a Solution


What i did was that i solved for the mass which i got was .04012 and then i used that mass in the ideal gas law with the new pressure of 150kPa to get a new volume of .167 m^3 is this the right approach and answer?
 
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That's a fine approach, but be sure to answer the precise question asked: How big is the balloon?

Rather than calculate the mass, since it's constant, you could have just used:
P1V1 = P2V2.
 
By asking how big the balloon is doesn't it mean give the volume or what do you think i should put down?
 
You want the volume of the balloon, not the total volume.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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