How Can Amplitude Decay be Modeled with a Pendulum and Friction Coefficient?

AI Thread Summary
A pure tone sine wave can be modeled using a pendulum, where the amplitude decay is influenced by the friction coefficient. To replicate a specific frequency, such as middle C at 261.6 Hz, one can use the formula for the frequency of a pendulum, which involves gravitational acceleration and pendulum length. The decibel level of the sound is affected by distance, and understanding the relationship between intensity and amplitude is crucial. However, determining the rate of decay remains complex and may require advanced equations or computer modeling. Overall, while the basic principles are clear, practical implementation of these concepts in a physical model is challenging.
satori20
Messages
1
Reaction score
0
Basic premise: a pure tone sine wave can be modeled with a pendulum and the rate of amplitude decay can be manipulated with a friction coefficient.

So... does anyone know how this is actually done? In other words if you picked a pure tone (let's say middle C @ 261.6 Hz) initiated at a certain dB (let's say 50dB), how would you factor in rate of decay and how would you replicate this with a literal physical pendulum?

I know this is a complex question and I'm not even sure anyone is doing this but there's got to be equations and computer modeling that does. Obviously I'm just learning about this so the simplest explanation possible would be wonderful. 1st post here btw, so I hope it's in the right area :) Thanks!
 
Physics news on Phys.org
Here's something...

Frequency of a pendulum = \frac{1}{2\pi}\sqrt{\frac{g}{L}}

So, the length of your pendulum will be about 3.6 microns.

The decibel level depends on your distance. The logic would be

Intensity level => intensity => power => energy => amplitude

So this could tell you how far the pendulum moves (if large--which it probably is--it may invalidate the previous formula), but not the rate of decay.
 
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
Back
Top