How Can Energy, Work, and Power Increase Ski Race Speeds?

AI Thread Summary
Increasing speed in a ski race can be explained through the relationship between energy, work, and power. The formula power equals work divided by time (P = W/t) indicates that performing more work in a shorter time results in greater power output, which translates to higher speeds. The concept of horsepower can also be applied, as one horsepower equals 750 watts, illustrating the importance of power in achieving faster speeds. Understanding how to maximize work and minimize time is crucial for improving performance in skiing. Overall, effective energy management is key to enhancing ski race speeds.
hockey45
Messages
4
Reaction score
0
hey guys,
here is the question i attempted.
Use the concept of energy,work and power to explain how you might increase the speed you can attain in a ski race?

power= W/t=E/T. i don't really get this question. is it that the more work you do is a small amount of time the more power you have so u are able to go fater in a ski race. can i connect this question to horse power. 1 hp=750W
thank you
 
Physics news on Phys.org
hockey45 said:
is it that the more work you do is a small amount of time the more power you have so u are able to go fater in a ski race.

I don't understand your question. Could you rephrase it?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top