How Can Fixed Points Determine Solutions in Differential Equations?

cummings12332
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Homework Statement



QQ截图20121202233027.png



The Attempt at a Solution



set x(t)=1+∫2cos(s(f^2(s)))ds(from 0 to t) then check x(0)=1+∫2cos(s(f^2(s)))ds(from 0 to 0)=1 then the initial condition hold, by FTC, we have dx(t)/dt=2cos(tx^(t)), then solutions can be found as fixed points of the map

but for secound part [0,T] i don't know how to begin can anyone help me ?
 
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cummings12332 said:

Homework Statement



View attachment 53573


The Attempt at a Solution



set x(t)=1+∫2cos(s(f^2(s)))ds(from 0 to t) then check x(0)=1+∫2cos(s(f^2(s)))ds(from 0 to 0)=1

Shouldn't that f be an x in this case?

but for secound part [0,T] i don't know how to begin can anyone help me ?

You have a map \Theta:\mathcal{C}([0,T],\mathbb{R})\rightarrow \mathcal{C}([0,T],\mathbb{R}) such that

\Theta(f):[0,T]\rightarrow \mathbb{R}:t\rightarrow 1+\int_0^t 2\cos(sf^2(s))ds

Strictly speaking, you first need to check that \Theta(f) is in fact continuous before you can say that the codomain of \Theta is \mathcal{C}([0,T],\mathbb{R}).

Now, you need to find out when \Theta is a contraction. Can you tell us what that means??

Also, here is a LaTeX guide on how to post mathematical equations: https://www.physicsforums.com/showpost.php?p=3977517&postcount=3 It would help us a lot if you would use this to make your equations more readable.
 
micromass said:
Shouldn't that f be an x in this case?
You have a map \Theta:\mathcal{C}([0,T],\mathbb{R})\rightarrow \mathcal{C}([0,T],\mathbb{R}) such that

\Theta(f):[0,T]\rightarrow \mathbb{R}:t\rightarrow\ 1+\int_0^t 2\cos(sf^2(s))ds<br /> <br /> Strictly speaking, you first need to check that \Theta(f) is in fact continuous before you can say that the codomain of \Theta is \mathcal{C}([0,T],\mathbb{R}).<br /> <br /> Now, you need to find out when \Theta is a contraction. Can you tell us what that means??<br /> <br /> Also, here is a LaTeX guide on how to post mathematical equations: <a href="https://www.physicsforums.com/showpost.php?p=3977517&amp;postcount=3" class="link link--internal">https://www.physicsforums.com/showpost.php?p=3977517&amp;postcount=3</a> It would help us a lot if you would use this to make your equations more readable.
<br /> <br /> how to say that \Theta(f) is continuous? i just don&#039;t know how to prove here. if it is then i know how to solve the problem now,many thanks
 
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cummings12332 said:
how to say that \Theta(f) is continuous?

Fundamental theorem of calculus.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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