How Can I Calculate the Force and Distance Between Protons in a Triangle?

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To calculate the distance between the third proton in a triangle formed by three protons, the known distances are 15 mm and 20 mm. The third side can range from 0 to 35 mm unless additional information is provided. If there is a right angle at Proton B, the Pythagorean theorem can be applied to find the unknown distance. Forces between the protons have been calculated using Coulomb's law, yielding values of 1.02 E -24 and 5.76 E -25. Further clarification on the triangle's geometry is necessary to proceed with the calculations.
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Hi,

There are 3 Protons (P) that form a triangle.
distance PA-PB -->15mm
distance PB-PC -->20mm
distance PA-PC --> unknown

I have to calculate the last distance and the forces between the protons by using coulomb´s laws.

I tried to calculate the force between AB and BC:
F1=1.02 E -24
F2=5.76 E -25

Now I don´t know what to do next? Can I use the a²+b²=c² for either the Fore or the distance?


Thanks
jawo3
 
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You've got a triangle with 2 known sides 15 and 20. The third side could be anywhere from 0 to 35 mm and still form a triangle. Do we have any more information to help us decide what the 3rd side is? Something about the forces, perhaps?
 
The teache or the problem didn´t say it but on the picture that I got it looks like there is a right angle, where Proton B is.
 
Well, that makes it easy. Just a geometry question, no physics involved.
 
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