How can I calculate the lift of a helium balloon?

In summary: If a bag, then the more helium you put in, the less lift you'll get.In summary, a helium balloon filled with gas at atmospheric pressure will have a maximum lift of W grams, provided the balloon and helium weigh less than the displaced air.
  • #1
kenewbie
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Say I want to send a helium balloon into the sky. For all intents and purposes this balloon is circular, with volume V. I will fill it with helium to the same pressure as the air outside it (I assume that this is important). The weight of the balloon and the payload is W.

So, I assume I have to calculate the weight of the helium + balloon, and, somehow, the weight of the air that the balloon replaces. So if the helium and the balloon is g grams lighter than the air would be, then I have g grams of lift?

And how would I go about converting g grams of lift to meters per second?

If anyone can help me out with some ways to calculate this, I would be very grateful. If there are important variables that I have left out, I certainly would appreciate that being pointed out aswell.

k
 
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  • #2
To calculate the weight of the gas displaced, you have to use the percent mixture of nitrogen, oxygen, CO2 ect. I am pretty sure that at STP the ratio is 24 liters per one mole of gas particles.

For calculating the rate of assent, since you already know the weight of the craft and the lift, just use Force=Mass*Acceleration
 
  • #3
Hi. Your statement is essentially right. You've got a balloon with weight W (including the Helium) that displaces a volume V of air. This air has a weight w, so the effective lifting force is equal to w minus W.

F = w - W

Irrelevant a this basic level: the shape of the balloon, the helium pressure. Of course, at greater pressure the He weights more, but this has already been included in the total weight W.

Now, we've got an object of mass M = W / g subject to a force F, so it acquires an acceleration

a = F / M

And therefore, supposing it starts with zero initial velocity , the speed at any time t is equal to:

v = a * t

Of course, in a more realistic setup the acceleration of the balloon is countered by the friction, when the balloon attains its terminal speed, the friction is equal to the lift, and it ceases to accelerate upwards.
 
  • #4
Is this an elastic balloon or a bag? If elastic, you'll have to put the helium in under pressure, hence extra helium and less lift.
 
  • #5


To calculate the lift of a helium balloon, you will need to consider several factors such as the volume of the balloon, the pressure of the helium, the weight of the balloon and payload, and the weight of the air that the balloon displaces. The lift of the balloon is the difference between the weight of the helium and the weight of the air it displaces. This can be calculated using the following formula:

Lift = V * (ρ_helium - ρ_air) * g

Where:
- V is the volume of the balloon
- ρ_helium is the density of helium
- ρ_air is the density of air
- g is the acceleration due to gravity

To calculate the weight of the helium and the balloon, you will need to know the density of helium. This can be found in a table of physical constants or by conducting experiments. The weight of the air that the balloon displaces can be calculated using the ideal gas law, which relates the pressure, volume, and temperature of a gas.

Once you have calculated the lift, you can convert it to meters per second by using the following formula:

Lift (m/s) = Lift (grams) / (ρ_air * V)

Where:
- ρ_air is the density of air
- V is the volume of the balloon

It is important to note that there may be other variables that could affect the lift of the balloon, such as wind speed and temperature. It is also important to consider the stability and design of the balloon to ensure safe and accurate calculations. I would recommend consulting with a qualified engineer or conducting further research to ensure accurate results.
 

1. How does a helium balloon rise?

Helium balloons rise due to the principle of buoyancy. Helium is lighter than air, so it creates an upward force that is greater than the downward force of gravity. This allows the balloon to float upwards.

2. What keeps a helium balloon from rising forever?

Helium balloons eventually stop rising because the air in the atmosphere becomes less dense as you go higher. At a certain point, the upward force of the helium is equal to the downward force of the surrounding air, causing the balloon to reach equilibrium and stop rising.

3. How much weight can a helium balloon lift?

The amount of weight a helium balloon can lift depends on the size and amount of helium in the balloon. A standard 11-inch balloon can lift about 0.5 grams, while larger balloons can lift several pounds.

4. What happens if I add too much weight to a helium balloon?

If too much weight is added to a helium balloon, it will no longer be able to overcome the downward force of gravity and will start to descend. The balloon may also pop if the weight is too heavy for it to handle.

5. How long will a helium balloon stay in the air?

The amount of time a helium balloon stays in the air depends on various factors, such as the size of the balloon, the amount of helium in it, and the surrounding air conditions. On average, a standard helium balloon can stay afloat for about 8-10 hours before it starts to lose its lift and deflate.

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