I How can I confirm Lz=ħ,0,-ħ using operators and eigenfunctions?

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kenyanchemist
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Hi,
I have a question
Given the function
LzYilm(θ,ϕ) =mħYilm(θ,ϕ)
What steps can I take to confirm that
Lz=ħ,0,-ħ
 
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kenyanchemist said:
I have a question
Given the function
LzYilm(θ,ϕ) =mħYilm(θ,ϕ)
What steps can I take to confirm that
Lz=ħ,0,-ħ

you are writing an eigen value equation for the z component of angular momentum operator called Lz
Ylm are spherical harmonics which are eigen functions of L^2 and Lz
if L=1 then m can take values +1, 0, -1 so the possible eigen values will be -h bar, 0, hbar

now you are asking what steps to confirm - then you can write the form of Lz and apply on spherical harmonics with l=1 and see what possible values comes out from eigen value equation.
 
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Umm... how do I go about that?! Please understand am like super new on quantum mechanics
Please show me :cry::cry:
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
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