How can I factor a 3rd order polynomial using the cubic formula?

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Homework Help Overview

The original poster seeks assistance with factoring a third-order polynomial, specifically the expression x^3 + 8x^2 - 21x + 10, in the context of finding eigenvalues of a matrix in linear algebra. They express uncertainty about the factoring process and mention a lack of attempts to solve the problem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the rational root test and suggest checking factors of the constant term. There is mention of polynomial division and the cubic formula as potential methods for finding roots. Some express concern about the tediousness of these methods.

Discussion Status

The discussion is ongoing, with participants exploring various methods for factoring the polynomial. There is acknowledgment of the complexity involved, particularly with irrational roots, and some participants suggest alternative approaches, including numerical solutions and online tools.

Contextual Notes

Participants note that the polynomial has irrational roots and that the original poster may have chosen a particularly challenging example. There is also a reference to homework constraints regarding the use of specific methods for finding eigenvalues.

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Homework Statement


What are the steps to factoring 3rd order polynomials like x^3+8x^2-21x+10?
It's to find eigenvalues of a matrix in linear algebra, I completely forgot how to factor and it's killing me.

Homework Equations





The Attempt at a Solution


None, unless its a polynomial that I can factor by grouping, I have no clue how to begin.
 
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EDIT: Nevermind the below, that factor trick (the 'rational root test') doesn't work in this case. The discriminant is positive, but it turns out that all three roots are irrational.

For a cubic polynomial with integer coefficients, which is what you have, I believe one of the roots is typically a factor of the constant term. So, try the factors of 10 and see if one of them is a root. Once you've figured out one of the roots, you can factor an (x-root) term out by polynomial division, leaving you with (x-root)*quadratic, and the quadratic you can factor with the quadratic formula.
 
Last edited:
:( so the pq thing with synthetic and what-the-other-one's-name division?
I don't know why i didnt think of it (but that sounds really tedious).
Thanks for your help! :)
 
Got it, so i happened to pick the only example in the book of a matrix with irrational eigenvalues. I'm still not so sure how to find the irrational roots of a 3rd order polynomial... i should change the name of this thread haha.
 
There's always the cubic formula, but using it is a bit... tedious. :eek:
 
eumyang said:
There's always the cubic formula, but using it is a bit... tedious. :eek:

To add to what "eumyang"" said, using the Cubic Formula to get an exact algebraic result is, indeed, a bit tedious.

On the other hand, if you are fine with numerical results, there are several free online utilities available; some of them are listed at the bottom of that Wikipedia page.

In addition, I refer you to an old post I made at the bottom of the following thread:

https://www.physicsforums.com/showthread.php?t=580075&page=2

A search of these forums would probably turn up much more information about factoring a cubic polynomial.
 

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