How can I find the adiabatic equation for real gases?

AI Thread Summary
To derive the real gas adiabatic equation, the Van der Waals equation can be a starting point, but it has limitations and may not apply universally. The discussion highlights a specific equation to solve: n Cv dT + an/V + nRT logV/ logbn = 0. The need for a detailed solution to obtain the exact equation for the adiabatic process is emphasized. Participants are encouraged to provide insights on how to manipulate this equation effectively. Understanding the behavior of real gases under various conditions is crucial for accurate modeling.
AudriusR
Messages
11
Reaction score
0
Hey!
Maybe anyone knows, how to get real gas adiabatic equation. It's not a big deal, when you need to get ideal gas equation, but I haven't got any ideas about real gas. I'm wondering maybe it's something with Van der Waals equation, but in my opinion it can't be like this :

(p+a/V2)(V+b)\gamma = constant


So any ideas? It would be great, if you could show me detailed answer.
 
Last edited:
Physics news on Phys.org
I got an equation to solve for this, maybe anyone could help :

n Cv dT + an/V + nRT logV/ logbn = 0

How to get exact equation for adiabatic process from this ?
 
The van der Vaal equation does not hold for all gases or all conditions it has limits.
 
Thread ''splain this hydrostatic paradox in tiny words'
This is (ostensibly) not a trick shot or video*. The scale was balanced before any blue water was added. 550mL of blue water was added to the left side. only 60mL of water needed to be added to the right side to re-balance the scale. Apparently, the scale will balance when the height of the two columns is equal. The left side of the scale only feels the weight of the column above the lower "tail" of the funnel (i.e. 60mL). So where does the weight of the remaining (550-60=) 490mL go...
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Scalar and vector potentials in Coulomb gauge Assume Coulomb gauge so that $$\nabla \cdot \mathbf{A}=0.\tag{1}$$ The scalar potential ##\phi## is described by Poisson's equation $$\nabla^2 \phi = -\frac{\rho}{\varepsilon_0}\tag{2}$$ which has the instantaneous general solution given by $$\phi(\mathbf{r},t)=\frac{1}{4\pi\varepsilon_0}\int \frac{\rho(\mathbf{r}',t)}{|\mathbf{r}-\mathbf{r}'|}d^3r'.\tag{3}$$ In Coulomb gauge the vector potential ##\mathbf{A}## is given by...
Back
Top