How can I find the velocity and acceleration of a particle in 2-dimensions?

  • Thread starter Thread starter Filenes
  • Start date Start date
AI Thread Summary
To find the velocity and acceleration of a particle in two dimensions, the position vector is given as r = (7.40 i - 6.60t² j) m. The velocity can be derived by differentiating the position vector with respect to time, resulting in v = (0 i - 13.20t j) m/s. The acceleration is found by differentiating the velocity, yielding a = (0 i - 13.20 j) m/s², indicating constant acceleration in the j-direction. For part (b), at t = 2.00 s, the position is r = (7.40 i - 26.40 j) m and the velocity is v = (0 i - 26.40 j) m/s. Understanding these calculations involves recognizing the definitions of instantaneous velocity and acceleration as derivatives of position with respect to time.
Filenes
Messages
4
Reaction score
0

Homework Statement


The vector position of a particle varies in time according to the expression r = (7.40 i - 6.60t2 j) m.
(a) Find expressions for the velocity and acceleration as functions of time. (Use t, i, and j as necessary.)
v =
a =
(b) Determine the particle's position and velocity at t = 2.00 s.
r =
v =


Homework Equations


kinematic of 2-dimen
r= v/t

The Attempt at a Solution


I found (b) r.. but i have no clue how to start part (A), i thought since R = V/t then
r =(7.40i - 6.60t^2)/ t but that was wrong.. so I'm thinking that r should be change into something. Any help would be great
 
Physics news on Phys.org
What is the definition of Velocity and Acceleration with respect to distance and time?
 
r/t is average velocity. your trying to find the instaneous rate of change. which means its time to put that calc 1 to use!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top