How can I generalize the result for the n=2 case to a larger set of numbers?

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The discussion focuses on generalizing the result for the case of n=2 to a larger set of numbers in an ordered field. The initial case shows that the ratio (a+c)/(b+d) remains between the minimum and maximum of a/b and c/d when b and d are positive. A suggestion is made to use proof by induction for the general case, with a reformulation of the n=2 case to highlight the convex combination of the ratios a_i/b_i. By demonstrating that the weighted averages of these ratios fall within the bounds set by the minimum and maximum, the generalization can be established. The conversation emphasizes the importance of recognizing the properties of ordered fields and convex combinations in the proof process.
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Homework Statement


a,b,c,d in a ordered set K and b and d>0
Show that \frac{a+c}{b+d} stay between the minimum and max from \frac {a}{b} and \frac {c}{d}. Generalize for a_1,\hdots,a_n,b_1,\hdots,b_n \in K with b_1\hdots,b_n >0 so \frac{a_1+\hdots+a_n}{b_1+\hdots+b_n} is between the max and min elements from \frac{a_1}{b_1},\hdots,\frac{a_n}{b_n}

I could do it for the the first case but in a way it's impossible to generalize
any ideas?
tks in advance
 
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to correct, it`s a ordered field
 
if u consider a/b<c/d
u can do a/b - (a+c)/(b+d)}=(ad-bc)/(b(b+d))>0
and c/d - (a+c)/(b+d)}=(bc-ad)/(b(b+d))>0
and done

but them using samething for generalizing i couldn't make it :(
 
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Looks like proof by induction would work.
 
Let's redo the n=2 case in a way it will be easier to generalize. Write (a1+a2)/(b1+b2)=(b1/(b1+b2))*(a1/b1)+(b2/(b1+b2))*(a2/b2). Notice that the bi/(b1+b2) terms are positive and sum to 1. (This means (a1+a2)/(b1+b2) is in the 'convex hull' of the bi/ai.) If I replace the ai/bi by their minimum and maximum, what do I conclude?
 
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