How can I integrate this function using substitution?

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Homework Help Overview

The discussion revolves around evaluating the definite integral of the function \(\int_{1}^{2} \frac{\sin t}{t} dt\). Participants are exploring methods of integration, particularly substitution and integration by parts, while questioning the feasibility of finding a closed form for the integral.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use substitution with \(u = \sin(t)\) and \(u = \frac{1}{t}\) but finds these approaches unhelpful. Another participant suggests a combination of integration by parts but questions how to proceed with the resulting integral. There is also a discussion about the potential lack of a closed form for the integral.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning the methods used. Some guidance has been offered regarding integration by parts, but there is no clear consensus on the best approach or the existence of a closed form for the integral.

Contextual Notes

Participants are navigating the complexities of integration techniques and expressing uncertainty about the notation and methods, indicating a potential gap in understanding the integration process.

ada0713
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Homework Statement


Evaluate the definite integral of the following
\int (from 1 to 2) \frac{sin t}{t} dt


The Attempt at a Solution



I am actually stuch from the very beginning.
I tried to set u=sin(t) but this doesn't help much because (sint)'=cost and
this is going to make the problem more complicated.
I also set u=1/t but the derivative of 1/t has nothing to do with
the function as well.

(Perhaps I shouldn't integrate the function by substitution)

Please help me with the start!
 
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I set:
u=sint dv=1/t dt
du=-cost v=lnltl

\int [from 1 to 2] (sint)(1/t) dt

= [(sint)(lnltl)]^{1}_{2} -\int[from 1 to 2] lnltl (-cost)

How do I integrate the red part?
should I do the by parts again?
 
Well...I do not think there is any closed form of that integral.(To my knowledge) You may need something more than integration by parts.
 
For your latex

\int_1^2

\frac 1 t or \frac{1}{t} - use the brackets when you have more than one letter per term

Or maybe you were lazy :-p
 
roco, where did you learn the \int_1^2 notation? I never figured it out, at least not from the latex code reference PDF file.
 
Defennnder said:
roco, where did you learn the \int_1^2 notation? I never figured it out, at least not from the latex code reference PDF file.
\int_1^2

Click on the latex and you will see the code.
 

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