How can I integrate this rational function using partial fractions?

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SUMMARY

The integration of the rational function \(\int\frac{\frac{1}{3}x+\frac{2}{3}}{x^{2}-x+1}\) can be effectively approached using partial fraction decomposition. The key steps involve completing the square of the denominator \(x^2 - x + 1\) to transform it into a more manageable form. Once the denominator is expressed as \((a+b)(a-b)\), the function can be decomposed into partial fractions, allowing for straightforward integration. Although the process may seem tedious, it is a definitive method for solving this type of integral.

PREREQUISITES
  • Understanding of rational functions and their properties
  • Knowledge of partial fraction decomposition techniques
  • Familiarity with completing the square for quadratic expressions
  • Basic integration techniques, including trigonometric substitution
NEXT STEPS
  • Study the method of partial fraction decomposition in detail
  • Practice completing the square for various quadratic functions
  • Explore integration techniques involving trigonometric substitutions
  • Review examples of integrating rational functions with complex denominators
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators seeking to enhance their teaching methods for rational function integration.

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Homework Statement


[tex]\int[/tex][tex]\frac{\frac{1}{3}x+\frac{2}{3}}{x^{2}-x+1}[/tex]

Homework Equations



This is the result of a partial fraction integration. I don't think a direct u-substitution will work or an integration by parts.

The Attempt at a Solution



I don't know which I should use! We learned so many and none seem to work nicely in this case. Should I try to do a trigonometric substitution? That is my best guess, but since there is no radical I have no idea how to implement it!

Any sort of hint would be great. I'm just not "seeing it" ;)
 
Last edited:
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Complete the square of the denominator then break it up using (a+b)(a-b) = a^2 - b^2. From here you can do it by partial fractions, though it appears tedious.
 

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