How can I prove it? (injection, bijection, surjection)

gotmejerry
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Homework Statement


How can I prove this?

If g°f is a bijective function, then g is surjective and f is injective.

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The Attempt at a Solution

 
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First what does g°f mean
what does bijective mean
what does surjective mean
what does injective mean
 
Start of with let g of f be a bijection, than state of the definition of a bijection. From there you can prove what must be true of g and f for g of f to meet the definition.
 
I can see why it is need to be true, when I draw it, unfotunately I cannot write down the solution in a mathematical way.
 
To start say
Let g°f be a bijective function.

then what can you say about g°f
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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