How can I prove this binomial identity?

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Homework Statement


Prove that the following binomial identity holds:

{n+k-1 \choose k} = \sum_{i=1}^k {k-1\choose i-1}{n\choose i}


The Attempt at a Solution



One of the methods I've tried is to use induction on the variable n, but while trying this I got stuk on rewriting the binomial coefficients... can someone give me a hint if I can use another simple binomial identity for this?

Another thing I have tried to do is to look at the generating function of the left hand side, and then try to rewrite this to a generating function for the right hand side, but that didn't succeed either...

Can someone point me a little bit in the right direction?
 
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Try finding two ways to count the number of ways you can choose k balls from a box containing n red balls and k-1 red balls.

Also note that
{k-1 \choose i-1} = {k-1 \choose k-i}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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