How can I simplify this expression involving summation and factorials?

AI Thread Summary
The discussion focuses on simplifying the expression e^{-(\lambda + \mu)}\sum_{k=0}^w \frac{\lambda^k \mu^{(w-k)}}{k!(w-k)!}. Participants note that the sum resembles a binomial expansion, which leads to the conclusion that the expression can be simplified to e^{-(\lambda + \mu)}\frac{(\lambda + \mu)^w}{w!}. The conversation highlights the importance of recognizing the binomial form to facilitate simplification. Ultimately, the simplification effectively combines the terms involving factorials and exponentials. This approach clarifies the relationship between the original expression and its simplified form.
Polymath89
Messages
27
Reaction score
0
I need to simplify this expression and I don't know how to deal with the factorials in the sum

e^{-(\lambda + \mu)}\sum_{k=0}^w \frac{\lambda^k \mu^{(w-k)}}{k!(w-k)!}

Can anybody give me a hint on how to sum over the factorials?
 
Mathematics news on Phys.org
Polymath89 said:
I need to simplify this expression and I don't know how to deal with the factorials in the sum

e^{-(\lambda + \mu)}\sum_{k=0}^w \frac{\lambda^k \mu^{(w-k)}}{k!(w-k)!}

Can anybody give me a hint on how to sum over the factorials?
This is already pretty simplified. Do you mean that you want to expand it?
 
Sorry for not being clear, yes I want to expand the sum.
 
The sum looks almost like a binomial expansion.
net result e-(λ+μ)(λ+μ)w/w!.
 
mathman said:
The sum looks almost like a binomial expansion.
net result e-(λ+μ)(λ+μ)w/w!.
Thank you very much.
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Back
Top